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fix: 修改排列三和排列五逻辑

This commit is contained in:
chenwj113 2023-07-10 16:54:10 +08:00
parent 7c71d61f3a
commit 8a707eb739
2 changed files with 29 additions and 13 deletions
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35
lottery/pls.py
View File

@ -5,15 +5,21 @@ import pandas as pd
a = np.arange(1000)
l = set([ "".join(sorted(f"{i:03d}")) for i in a ])
f1 = lambda number: True if '0' in number or '3' in number else False
# 跨度
span_list = [int(i[2]) - int(i[0]) for i in l]
span_df = pd.value_counts(span_list)
print(span_df.to_dict())
print((220/span_df).to_dict())
f1 = lambda number: True if '8' in number or '5' in number else False
f2 = lambda number: True if sum(map(int, number)) in [10, 13, 14, 16, 17] else False
arr1 = list(filter(f1, l))
# print(len(arr1))
# print(arr1)
arr2 = list(filter(f2, arr1))
print(len(arr2))
print(arr2)
# print(len(arr2))
# print(arr2)
sum_list = [ sum(map(int, list(i))) for i in l]
sum_df = pd.value_counts(sum_list)
@ -22,6 +28,7 @@ print((220/sum_df).to_dict())
# 组三
group3 = [ i for i in l if len(set(i)) == 2]
sum_group3_dict = {i: [] for i in np.arange(28)}
for i in group3:
sum_group3_dict[sum(map(int, list(i)))].append(i)
@ -39,22 +46,24 @@ for i in group6:
# for i in range(5, 20):
# _result = [item for item in sum_group3_dict[i]]
f1 = lambda number: len([i for i in number if int(i) %2 == 0]) != 0
f2 = lambda number: len([i for i in number if int(i) %2 == 1]) != 0
f3 = lambda n: True if int(n[1]) - int(n[0]) == 1 or int(n[2]) - int(n[1]) == 1 else False
f4 = lambda number: True if 'a' not in number else False
f5 = lambda number: True if '4' in number or '6' in number else False
f6 = lambda number: True if len(set('279').difference(number)) == 2 else False
arr = list(filter(f5, group3))
print(arr)
print(len(arr))
for i in sum_group6_dict.keys():
f1 = lambda number: len([i for i in number if int(i) %2 == 0]) != 0
f2 = lambda number: len([i for i in number if int(i) %2 == 1]) != 0
f3 = lambda n: True if int(n[1]) - int(n[0]) == 1 or int(n[2]) - int(n[1]) == 1 else False
f4 = lambda number: True if '3' in number else False
f5 = lambda number: True if '2' in number or '5' in number or '7' in number else False
f6 = lambda number: True if len(set('279').difference(number)) == 2 else False
if i in [12, 13, 14, 15, 16, 17]:
if i in range(11, 21):
# result = sum_group6_dict[i] + sum_group3_dict[i]
result = sum_group3_dict[i]
print("-"*15 + "组三" + "-"*15)
print(i, list(filter(f4, result)))
print(i, list(sorted(filter(f4, result))))
result = sum_group6_dict[i]
print("-"*15 + "组六" + "-"*15)
print(i, list(filter(f4, result)))
print(i, list(sorted(filter(f4, result))))
print()

7
lottery/plw.py
View File

@ -2,6 +2,13 @@ import numpy as np
import pandas as pd
import math
from sqlalchemy import create_engine
engine = create_engine("mysql+pymysql://test:123456@localhost/lottery?charset=utf8")
conn = engine.connect()
sql = """SELECT draw_issue, draw_code, sum_num FROM plw ORDER BY id DESC LIMIT 10"""
df = pd.read_sql(sql, conn)
print(df)
a = np.arange(100000)
l = set([ f"{i:05d}" for i in a ])