51 lines
1.6 KiB
Python
51 lines
1.6 KiB
Python
import numpy as np
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import pandas as pd
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a = np.arange(1000)
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l = set([ "".join(sorted(f"{i:03d}")) for i in a ])
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sum_list = [ sum(map(int, list(i))) for i in l]
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sum_df = pd.value_counts(sum_list)
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# print(sum_df.to_dict())
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# print(220/sum_df)
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# 组三
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group3 = [ i for i in l if len(set(i)) == 2]
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sum_group3_dict = {i: [] for i in np.arange(28)}
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for i in group3:
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sum_group3_dict[sum(map(int, list(i)))].append(i)
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# 组六
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group6 = [ i for i in l if len(set(i)) == 3]
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sum_group6_dict = {i: [] for i in np.arange(28)}
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for i in group6:
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sum_group6_dict[sum(map(int, list(i)))].append(i)
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# for i in sum_group3_dict.keys():
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# f3 = lambda number: True if '7' not in number else False
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# print(i, list(filter(f3, sum_group3_dict[i])))
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# print(sum_group3_dict)
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# sum_group3 = [ sum(map(int, list(i))) for i in group3]
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# print(pd.value_counts(sum_group3).to_dict())
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# for i in range(5, 20):
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# _result = [item for item in sum_group3_dict[i]]
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for i in sum_group6_dict.keys():
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f1 = lambda number: len([i for i in number if int(i) %2 == 0]) != 0
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f2 = lambda number: len([i for i in number if int(i) %2 == 1]) != 0
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f3 = lambda number: True if max(map(int, number)) - min(map(int, number)) != 2 else False
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f4 = lambda number: True if '3' not in number else False
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f5 = lambda number: True if 'a' not in number else False
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if i in [12, 17]:
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result = sum_group6_dict[i] + sum_group3_dict[i]
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print(i, list(filter(f1, result)))
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# print(i, sum_group3_dict[i])
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# 连号
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result = []
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for i in l:
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a = np.array(list(map(int, i)))
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if int(np.max(a) - np.median(a)) == 1 or int(np.median(a) - np.min(a)) == 1:
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result.append(i)
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